Step 1 :Given that the mean (μ) is 100, the standard deviation (σ) is 15, and the IQ score (x) is 115, we can calculate the z-score using the formula z = (x - μ) / σ.
Step 2 :Substitute the given values into the formula to get z = (115 - 100) / 15.
Step 3 :Simplify the expression to get z = 15 / 15.
Step 4 :Therefore, the z-score for an IQ of 115 is \(\boxed{1.0}\). This means that an IQ of 115 is 1 standard deviation above the mean.