Step 1 :The given equation is \(6 \sin \left(\frac{\theta}{2}\right)=6 \cos \left(\frac{\theta}{2}\right)\). We can simplify this equation by dividing both sides by 6, which gives us \(\sin \left(\frac{\theta}{2}\right)=\cos \left(\frac{\theta}{2}\right)\).
Step 2 :We know that \(\sin \left(\frac{\theta}{2}\right)=\cos \left(\frac{\theta}{2}\right)\) when \(\frac{\theta}{2} = 45^\circ\) or \(\frac{\theta}{2} = 225^\circ\), because \(\sin 45^\circ = \cos 45^\circ\) and \(\sin 225^\circ = \cos 225^\circ\).
Step 3 :So, we can solve for \(\theta\) by multiplying both sides of the equation by 2. This gives us \(\theta = 90^\circ\) and \(\theta = 450^\circ\). However, since we are looking for solutions in the interval \([0^\circ, 360^\circ)\), we discard the solution \(\theta = 450^\circ\).
Step 4 :Therefore, the solution to the equation is \(\theta = 90^\circ\).
Step 5 :Final Answer: The solution set is \(\boxed{90}\).