Solve the equation for exact solutions over the interval $\left[0^{\circ}, 360^{\circ}\right.$ ). \[ 2 \sqrt{3} \sin 2 \theta=-3 \] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is $\{\square\}$. (Type an integer or a decimal. Type your answer in degrees. Do not include the degree symbol in your answer. Use a comma to separate answers as needed.) B. The solution is the empty set.

Step 1 ：The given equation is \(2 \sqrt{3} \sin 2 \theta=-3\).

Step 2 ：Isolate the sine function to get \(\sin 2 \theta = -\frac{3}{2 \sqrt{3}}\).

Step 3 ：Simplify the right side to get \(\sin 2 \theta = -0.8660254037844387\).

Step 4 ：Use the inverse sine function to find the solutions for \(2 \theta\) in the interval \([0^\circ, 360^\circ]\). The solutions are \(150^\circ\), \(330^\circ\), \(120^\circ\), and \(300^\circ\).

Step 5 ：However, we need to divide these solutions by 2 to find the solutions for \(\theta\).

Step 6 ：Check if these solutions satisfy the original equation \(2 \sqrt{3} \sin 2 \theta=-3\).

Step 7 ：The solutions that satisfy the original equation are \(150^\circ\) and \(330^\circ\).

Step 8 ：Final Answer: The solution set is \(\boxed{150, 330}\).