Step 1 :Let \(a = 2 \tan^{-1} \frac{15}{8}\). Then \(\tan a = \tan(2 \tan^{-1} \frac{15}{8})\).
Step 2 :Using the double angle formula for tangent, we have \(\tan a = \frac{2 \cdot \frac{15}{8}}{1 - (\frac{15}{8})^2} = \frac{30}{64 - 225} = -\frac{30}{161}\).
Step 3 :Construct a right triangle with opposite side -30 and adjacent side 161. The hypotenuse is \(\sqrt{(-30)^2 + 161^2} = \sqrt{26081} = 161.5\).
Step 4 :Then, \(\sin a = \frac{-30}{161.5} = -\frac{6}{32.3}\) and \(\cos a = \frac{161}{161.5} = \frac{322}{322.3}\).
Step 5 :Using the double angle formula for sine, we have \(\sin 2a = 2 \sin a \cos a = 2 \cdot -\frac{6}{32.3} \cdot \frac{322}{322.3} = -\frac{3864}{10432.89}\).
Step 6 :Simplify the fraction to get the final answer: \(\boxed{-\frac{1932}{5216.445}}\).