Solve the triangle. \[ a=7, b=6, C=160^{\circ} \] $c \approx \square$ (Round to two decimal places as needed.) $A \approx \square^{\circ}$ (Round to one decimal place as needed.) $B \approx \square^{\circ}$ (Round to one decimal place as needed.)

Step 1 ：We are given two sides and an included angle of a triangle. We can use the Law of Cosines to find the third side, and then use the Law of Sines to find the other two angles.

Step 2 ：The Law of Cosines is given by: \(c^2 = a^2 + b^2 - 2ab\cos(C)\)

Step 3 ：The Law of Sines is given by: \(\frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)}\)

Step 4 ：We can use these formulas to find the values of c, A, and B.

Step 5 ：Given: a = 7, b = 6, C = 160 degrees

Step 6 ：Convert C to radians: C = 2.792526803190927

Step 7 ：Use the Law of Cosines to find c: c = 12.803678383418427

Step 8 ：Use the Law of Sines to find A: A = 10.777090179609665 degrees

Step 9 ：Use the Law of Sines to find B: B = 9.222909820390328 degrees

Step 10 ：Final Answer: \(c \approx \boxed{12.80}\), \(A \approx \boxed{10.8^\circ}\), \(B \approx \boxed{9.2^\circ}\)