Solve the triangle. \[ a=22.5 \quad b=15.9 \quad c=25.3 \] What is the degree measure of angle $A$ ? (Simplify your answer. Type an integer or a decimal. Round to the nearest tenth if needed.) What is the degree measure of angle $B$ ? (Simplify your answer. Type an integer or a decimal. Round to the nearest tenth if needed.) What is the degree measure of angle $\mathrm{C}$ ? (Simplify your answer. Type an integer or a decimal. Round to the nearest tenth if needed.)

Step 1 ：We are given the lengths of all three sides of a triangle and asked to find the measures of the angles. We can use the Law of Cosines to find the measures of the angles. The Law of Cosines states that for any triangle with sides of lengths a, b, and c, and an angle A opposite side a, the following equation holds: \[a^2 = b^2 + c^2 - 2bc \cos(A)\]

Step 2 ：We can rearrange this equation to solve for cos(A), and then use the inverse cosine function to find the measure of angle A. We can repeat this process to find the measures of angles B and C.

Step 3 ：Given that a = 22.5, b = 15.9, and c = 25.3, we can calculate cosA = 0.48058517910855897

Step 4 ：Using the inverse cosine function, we find that A = 61.3 degrees

Step 5 ：Final Answer: The degree measure of angle \(A\) is \(\boxed{61.3}\) degrees.