Solve the quadratic equation by using the square root property. (Enter your answers as a comma-separated list.) \[ (x-3)^{2}=7 \] \[ x= \]

Step 1 ：The square root property states that if \(x^2 = a\), then \(x = \sqrt{a}\) or \(x = -\sqrt{a}\). In this case, we have \((x-3)^2 = 7\), so \(x-3 = \sqrt{7}\) or \(x-3 = -\sqrt{7}\).

Step 2 ：Solving for \(x\) in both cases will give us the solutions to the equation.

Step 3 ：The solutions to the equation \((x-3)^{2}=7\) are \(x = 3 + \sqrt{7}\) and \(x = 3 - \sqrt{7}\).

Step 4 ：In decimal form, these are approximately \(x = 5.65\) and \(x = 0.35\).

Step 5 ：Final Answer: Therefore, the solutions are \(\boxed{5.65, 0.35}\).