Let $f(x)=4 x-1$ and $g(x)=x^{2}+5$ Find $(f \circ g)(-3)$

Step 1 ：Let's first find the value of \(g(-3)\). We substitute \(x = -3\) into the function \(g(x) = x^{2} + 5\).

Step 2 ：After calculating, we find that \(g(-3) = 14\).

Step 3 ：Next, we substitute this value into the function \(f(x) = 4x - 1\).

Step 4 ：After calculating, we find that \(f(14) = 55\).

Step 5 ：So, the value of \((f \circ g)(-3)\) is \(\boxed{55}\).