The city of Raleigh has 6800 registered voters. There are two candidates for city council in an upcoming election: Brown and Feliz. The day before the election, a telephone poll of 500 randomly selected registered voters was conducted. 191 said they'd vote for Brown, 261 said they'd vote for Feliz, and 48 were undecided. Give the sample statistic for the proportion of voters surveyed who said they'd vote for Brown. Note: The proportion should be a fraction or decimal, not a percent. This sample statistic suggests that we might expect voters to vote for Brown. of the 6800 registered Check Answer

Step 1 ：The city of Raleigh has 6800 registered voters. There are two candidates for city council in an upcoming election: Brown and Feliz. The day before the election, a telephone poll of 500 randomly selected registered voters was conducted. 191 said they'd vote for Brown, 261 said they'd vote for Feliz, and 48 were undecided.

Step 2 ：The sample statistic for the proportion of voters surveyed who said they'd vote for Brown can be calculated by dividing the number of voters who said they'd vote for Brown by the total number of voters surveyed. In this case, the total number of voters surveyed is 500 and the number of voters who said they'd vote for Brown is 191.

Step 3 ：Let's denote the number of voters who said they'd vote for Brown as \(brown\_voters\) and the total number of voters surveyed as \(total\_surveyed\).

Step 4 ：\(brown\_voters = 191\)

Step 5 ：\(total\_surveyed = 500\)

Step 6 ：We can calculate the sample statistic as follows: \(sample\_statistic = \frac{brown\_voters}{total\_surveyed}\)

Step 7 ：Substituting the given values, we get \(sample\_statistic = \frac{191}{500} = 0.382\)

Step 8 ：Final Answer: The sample statistic for the proportion of voters surveyed who said they'd vote for Brown is \(\boxed{0.382}\).