Solve the system by the substitution method. \[ \begin{aligned} x+3 y & =10 \\ y & =4 x-14 \end{aligned} \] Select the correct choice below and, if necessary, fill in the answer box within your choice. A. The solution set is (Type an ordered pair.) B. There are infinitely many solutions. The solution set is $\{(x, y) \backslash \square$. (Type an equation.) C. There is no solution. The solution set is $\varnothing$.

Step 1 ：The system of equations can be solved by substitution method. Here, the second equation is already solved for y. So, we can substitute y in the first equation with the expression from the second equation. This will give us an equation in terms of x only, which we can solve to find the value of x.

Step 2 ：Substitute y in the first equation with the expression from the second equation: \(x + 3(4x - 14) = 10\)

Step 3 ：Simplify the equation to find the value of x: \(13x - 42 = 10\)

Step 4 ：Solve the equation to find the value of x: \(x = 4\)

Step 5 ：Substitute x = 4 into the second equation to find the value of y: \(y = 4*4 - 14 = 2\)

Step 6 ：The solution set is \(\boxed{(4, 2)}\)