A model rocket is launched with an initial upward velocity of $70 \mathrm{~m} / \mathrm{s}$. The rocket's height $h$ (in meters) after $t$ seconds is given by the following. \[ h=70 t-5 t^{2} \] Find all values of $t$ for which the rocket's height is 35 meters. Round your answer(s) to the nearest hundredth. (If there is more than one answer, use the "or" button.) \[ t=\prod \text { seconds } \]

Step 1 ：The problem is asking for the time $t$ when the height $h$ of the rocket is 35 meters. This is a quadratic equation problem.

Step 2 ：We can solve it by setting the equation $70t - 5t^2 = 35$ and solving for $t$.

Step 3 ：We can use the quadratic formula to solve for $t$, which is $t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = -5$, $b = 70$, and $c = -35$.

Step 4 ：Substituting the values of $a$, $b$, and $c$ into the quadratic formula, we get two solutions for $t$, $t1 = 0.52$ and $t2 = 13.48$.

Step 5 ：Final Answer: The values of $t$ for which the rocket's height is 35 meters are \(\boxed{0.52}\) seconds or \(\boxed{13.48}\) seconds.