Step 1 :The standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. The variable z represents the number of standard deviations from the mean.
Step 2 :The probability that z is between -1.42 and 0 can be found by looking up the z-scores in the standard normal table and subtracting the probabilities.
Step 3 :The probability of z being less than 0 is 0.5 (since the standard normal distribution is symmetric about the mean).
Step 4 :The probability of z being less than -1.42 can be found from the standard normal table, which is approximately 0.0778.
Step 5 :Subtract the probability of z being less than -1.42 from the probability of z being less than 0 to find the probability that z is between -1.42 and 0: \(0.5 - 0.0778 = 0.4222\).
Step 6 :Final Answer: The probability that z is between -1.42 and 0 is approximately \(\boxed{0.4222}\).