Step 1 :The problem is asking for the probability of certain events given a known success rate for a football player completing a pass. This is a problem of geometric distribution, which is a probability distribution that describes the number of Bernoulli trials needed for a success to occur.
Step 2 :For part (a), the first pass he completes is the second pass, which means the first pass is a failure and the second pass is a success. The probability of this event is the product of the probability of failure on the first pass and the probability of success on the second pass.
Step 3 :For part (b), the first pass he completes is the first or second pass, which means either the first pass is a success, or the first pass is a failure and the second pass is a success. The probability of this event is the sum of the probabilities of these two scenarios.
Step 4 :Let's denote the probability of success as \(p_{success} = 0.631\) and the probability of failure as \(p_{failure} = 0.369\).
Step 5 :Then, the probability that the first pass he completes is the second pass is \(p_a = p_{failure} \times p_{success} = 0.232839\).
Step 6 :And the probability that the first pass he completes is the first or second pass is \(p_b = p_{success} + p_{failure} \times p_{success} = 0.863839\).
Step 7 :Final Answer: \(\boxed{(a)\, The\, probability\, that\, the\, first\, pass\, he\, completes\, is\, the\, second\, pass\, is\, approximately\, 0.233.}\)
Step 8 :Final Answer: \(\boxed{(b)\, The\, probability\, that\, the\, first\, pass\, he\, completes\, is\, the\, first\, or\, second\, pass\, is\, approximately\, 0.864.}\)