Problem

a $x^{2}-10 x+25=0$

Solution

Step 1 :Given the quadratic equation: \(x^{2}-10x+25=0\)

Step 2 :Use the quadratic formula: \(x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\)

Step 3 :Substitute the coefficients: a = 1, b = -10, and c = 25

Step 4 :Calculate the discriminant: \(\Delta = b^{2} - 4ac = (-10)^{2} - 4(1)(25) = 100 - 100 = 0\)

Step 5 :Substitute the discriminant and coefficients into the quadratic formula: \(x = \frac{-(-10) \pm \sqrt{0}}{2(1)}\)

Step 6 :\(x = \frac{10 \pm 0}{2}\)

Step 7 :\(\boxed{x = 5}\)

From Solvely APP
Source: https://solvelyapp.com/problems/7404/

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