Problem

Given that events $\mathrm{A}$ and $\mathrm{B}$ are independent with $P(A)=0.32$ and $P(B)=0.95$, determine the value of $P(A \cap B)$, rounding to the nearest thousandth, if necessary.

Solution

Step 1 :Given that events \(A\) and \(B\) are independent with \(P(A)=0.32\) and \(P(B)=0.95\), determine the value of \(P(A \cap B)\), rounding to the nearest thousandth, if necessary.

Step 2 :Since events A and B are independent, we can use the formula for the probability of the intersection of two independent events: \(P(A \cap B) = P(A) * P(B)\). We are given \(P(A) = 0.32\) and \(P(B) = 0.95\). We can plug these values into the formula and calculate the result.

Step 3 :\(P(A \cap B) = P(A) * P(B) = 0.32 * 0.95 = 0.304\)

Step 4 :\(\boxed{0.304}\)

From Solvely APP
Source: https://solvelyapp.com/problems/7399/

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