Find the equation of the tangent line to the function $f$ at $x=6$. \[ f(x)=-9 x^{2}+3 x-8 \] Show your work here \[ y= \]

Step 1 ：Find the derivative of the function: \(f'(x) = -18x + 3\)

Step 2 ：Evaluate the derivative at \(x = 6\): \(f'(6) = -105\)

Step 3 ：Find the value of the function at \(x = 6\): \(f(6) = -314\)

Step 4 ：Use the point-slope form to find the equation of the tangent line: \(y + 314 = -105(x - 6)\)

Step 5 ：\boxed{y = -105x + 630}