Problem
If the velocity of the object is given as \( V=12 t^{8}+3 t^{2} \) where \( x \) is in meters and \( t \) is in seconds. Find the instantaneous acceleration at \( 2 \mathrm{~S} \)
Solution
Step 1 ：\(\mathrm{Step~1:}~\frac{dV}{dt} = A(t) = \frac{d(12t^{8} + 3t^2)}{dt}\)
Step 2 ：\(\mathrm{Step~2:}~A(t) = 96t^7 + 6t\)
Step 3 ：\(\mathrm{Step~3:}~A(2) = 96(2)^7 + 6(2)\)
