Problem

If a \( 15 \mathrm{~kg} \) ball takes 54 seconds to strike the ground when released from rest, at what height (meter unit) was the ball dropped?

Solution

Step 1 :1. \( t = 54 \mathrm{~s} \)

Step 2 :2. \( g = 9.81 \mathrm{~m/s^2} \)

Step 3 :3. \( h = \frac{1}{2}gt^2 \)

Step 4 :4. \( h = \frac{1}{2}(9.81)(54^2) \)

Step 5 :5. \( h = 14345.14 \mathrm{~m} \)

From Solvely APP
Source: https://solvelyapp.com/problems/7363/

Get free Solvely APP to solve your own problems!

solvely Solvely
Download