QUESTION 1 Quadratic Equation Choose one $\cdot 5$ points 1. Solve $x^{2}+4 x-5=0$ using the quadratic formula \[ x_{1}=1, x_{2}=-5 \] \[ r_{1}=1, x_{2}=5 \] \[ x_{1}=-1, x_{2}=-5 \]

Step 1 ：Given the quadratic equation \(x^{2}+4 x-5=0\)

Step 2 ：Identify the coefficients as \(a = 1\), \(b = 4\), and \(c = -5\)

Step 3 ：Calculate the discriminant \(D = b^2 - 4ac = 36\)

Step 4 ：Use the quadratic formula to find the solutions for x: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)

Step 5 ：Substitute the values into the formula to get \(x_1 = -5.0\) and \(x_2 = 1.0\)

Step 6 ：Final Answer: The solutions to the equation are \(\boxed{x_{1}=-5, x_{2}=1}\)