Step 1 :The problem is asking to estimate the probability of getting at least 7 successes in a binomial distribution with parameters n=13 and p=0.5 using the normal distribution as an approximation. The conditions for using the normal approximation are met since both np and nq are greater than 5.
Step 2 :To use the normal approximation, we need to calculate the mean and standard deviation of the binomial distribution. The mean of a binomial distribution is np and the standard deviation is \(\sqrt{npq}\).
Step 3 :Then, we can use the normal distribution to approximate the probability. However, we need to apply the continuity correction since we are approximating a discrete distribution with a continuous one. So, instead of finding P(X >= 7), we find P(X > 6.5).
Step 4 :Finally, we standardize and use the standard normal distribution to find the probability.
Step 5 :The calculations are as follows: n = 13, p = 0.5, q = 0.5, mean = 6.5, std_dev = \(\sqrt{1.8027756377319946}\), x = 6.5, z = 0.0, prob = 0.5
Step 6 :This means that there is a 50% chance of getting at least 7 successes in a binomial distribution with parameters n=13 and p=0.5 when using the normal distribution as an approximation.
Step 7 :Final Answer: \(P(\text{ at least 7})= \boxed{0.500}\)