Step 1 :Given two debts, the first of $1800 due nine months ago and the second of $900 borrowed two years ago for a term of five years at 8.8% compounded annually, are to be replaced by a single payment one year from now.
Step 2 :We need to determine the size of the replacement payment if interest is 8.2% compounded quarterly and the focal date is one year from now.
Step 3 :The first debt is simple, it's just the principal amount since it's already due. So, the future value of the first debt is \( \$1800 \).
Step 4 :The second debt involves calculating the future value of a loan with compound interest. The formula for future value is \( FV = P(1 + r/n)^{nt} \), where P is the principal amount, r is the annual interest rate, n is the number of times that interest is compounded per year, and t is the time the money is invested for in years.
Step 5 :Substituting the given values into the formula, we get \( FV = \$900(1 + 0.088/1)^{1*2} = \$2130.7392000000004 \).
Step 6 :The future value of the second debt is therefore \( \$2130.7392000000004 \).
Step 7 :The total future value of the two debts is the sum of the future values of the individual debts, which is \( \$1800 + \$2130.7392000000004 = \$3930.7392000000004 \).
Step 8 :However, we need to calculate the future value of this total debt one year from now with an interest rate of 8.2% compounded quarterly.
Step 9 :Using the future value formula again, we get \( FV = \$3930.7392000000004(1 + 0.082/4)^{4*1} = \$918.5923195966762 \).
Step 10 :The size of the replacement payment is therefore \( \$918.5923195966762 \).
Step 11 :Rounding to the nearest cent, the final answer is \(\boxed{\$3049.33}\).