$17 \tan x>\sqrt{3}$

Step 1 ：Divide both sides of the inequality by 17: \(\tan x > \frac{\sqrt{3}}{17}\)

Step 2 ：Find the angle whose tangent is greater than \(\frac{\sqrt{3}}{17}\): \(x > 0.1015 \text{ radians}\) or \(x > 5.82 \text{ degrees}\)

Step 3 ：\(\boxed{x > 0.1015 \text{ radians} \text{ or } x > 5.82 \text{ degrees}}\)