Problem

Question 9 1 pts What is the probability they were in first class or they survived? (Put your answer in fraction form reduced to lowest terms.) Data breakdown of passenger who survived and died on the Titanic. \begin{tabular}{|c|c|c|c|c|c|} \hline & 1st & 2nd & 3rd & Crew & Total \\ \hline Survived & 203 & 118 & 178 & 212 & 711 \\ \hline Died & 122 & 167 & 528 & 673 & 1490 \\ \hline Total & 325 & 285 & 706 & 885 & 2201 \\ \hline \end{tabular}

Solution

Step 1 :Given the data breakdown of passengers who survived and died on the Titanic, we are asked to find the probability that a passenger was in first class or they survived.

Step 2 :We can calculate this by adding the probability of being in first class and the probability of surviving, and then subtracting the probability of both (since we are counting those twice).

Step 3 :The probability of an event is calculated by dividing the number of ways the event can occur by the total number of outcomes.

Step 4 :So, we need to calculate: 1. The probability of being in first class (number of first class passengers divided by total passengers) 2. The probability of surviving (number of survivors divided by total passengers) 3. The probability of being in first class and surviving (number of first class survivors divided by total passengers)

Step 5 :Then we add the first two probabilities and subtract the third.

Step 6 :Given that the total number of passengers is 2201, the number of first class passengers is 325, the number of survivors is 711, and the number of first class survivors is 203, we can calculate the probabilities as follows:

Step 7 :The probability of being in first class is \(\frac{325}{2201} \approx 0.1477\)

Step 8 :The probability of surviving is \(\frac{711}{2201} \approx 0.3230\)

Step 9 :The probability of being in first class and surviving is \(\frac{203}{2201} \approx 0.0922\)

Step 10 :Adding the first two probabilities and subtracting the third, we get the probability that a passenger was in first class or they survived is \(0.1477 + 0.3230 - 0.0922 \approx 0.3785\)

Step 11 :Final Answer: The probability that a passenger was in first class or they survived is approximately \(\boxed{\frac{3784643343934575}{10000000000000000}}\) or in reduced form \(\boxed{\frac{711}{1881}}\).

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