Step 1 :State the hypotheses for the one-mean z-test: \(H_0: \mu = 18mg\) and \(H_a: \mu < 18mg\).
Step 2 :Compute the value of the test statistic: \(z = -4.89\).
Step 3 :Determine the P-value: \(P = 0.000\).
Step 4 :Interpret the results: The calculated z-score is approximately -4.89, which means that the sample mean is approximately 4.89 standard deviations below the population mean. This is a significant deviation, suggesting that the average iron intake of adult females is indeed less than the recommended dietary allowance (RDA) of 18mg.
Step 5 :The P-value is 0.000, which is less than the significance level of 0.01. This means that the probability of observing a sample mean as extreme as 14.65mg, assuming the null hypothesis is true, is less than 1%. This is strong evidence against the null hypothesis.
Step 6 :Make a conclusion: Therefore, we reject the null hypothesis and conclude that the average iron intake of adult females is less than the recommended dietary allowance (RDA) of 18mg. \(\boxed{\text{Final Answer: At the 1% significance level, the data provides sufficient evidence to conclude that adult females are getting less than the RDA of iron, on average.}}\)