Find the slope of the line passing through the points $(-5,-2)$ and $(3,-9)$. $\square$ \begin{tabular}{|c|c|c|} \hline$\frac{\text { 믐 }}{}$ & $\square$ 믐 & Undefined \\ \hline$x$ & & 5 \\ \hline \end{tabular}

Step 1 ：The slope of a line passing through two points \((x_1, y_1)\) and \((x_2, y_2)\) can be found using the formula: \(m = \frac{y_2 - y_1}{x_2 - x_1}\)

Step 2 ：In this case, the two points are \((-5,-2)\) and \((3,-9)\). So, we can substitute these values into the formula to find the slope.

Step 3 ：\(m = \frac{-9 - (-2)}{3 - (-5)}\)

Step 4 ：\(m = -0.875\)

Step 5 ：Final Answer: The slope of the line passing through the points \((-5,-2)\) and \((3,-9)\) is \(\boxed{-0.875}\)