What is the equation of the line that goes through the points $(2,3)$ and $(4,6)$ ?

Step 1 ：Find the slope (m) using the formula \(m = \frac{{y2 - y1}}{{x2 - x1}}\). Substituting the given points into the formula, we get \(m = \frac{{6 - 3}}{{4 - 2}} = \frac{3}{2} = 1.5\).

Step 2 ：Find the y-intercept (b) by substituting one of the points and the slope into the equation \(y = mx + b\) and solving for b. Using the point (2,3), we get \(3 = 1.5 * 2 + b\), which simplifies to \(3 = 3 + b\), and further simplifies to \(b = 3 - 3 = 0\).

Step 3 ：Write the equation of the line by substituting m and b into the equation \(y = mx + b\), we get the equation of the line as \(y = 1.5x + 0\), or simply \(y = 1.5x\).

Step 4 ：Check the solution by substituting the coordinates of the second point (4,6) into the equation to check if it holds true: \(6 = 1.5 * 4 + 0\), which simplifies to \(6 = 6\). Since the left side equals the right side, the equation is correct.

Step 5 ：\(\boxed{y = 1.5x}\) is the equation of the line that goes through the points (2,3) and (4,6).