A 2m long uniform beam is supported at either end. A weight is hung 0.5m from the left support. If the weight is causing a clockwise moment of 100Nm, what is the mass of the weight?

Step 1 ：Step 1: We know that the moment (or torque) is given by the equation \(Moment = Force \times Distance\). Here, the force is the weight and the distance is 0.5m. So we can write the equation as \(100 Nm = Weight \times 0.5m\)

Step 2 ：Step 2: Rearrange the equation to find the weight. \(Weight = \frac{100 Nm}{0.5m} = 200N\)

Step 3 ：Step 3: We know that weight is the product of mass and gravity. So we can write the equation as \(200N = Mass \times 9.8m/s^2\)

Step 4 ：Step 4: Rearrange the equation to find the mass. \(Mass = \frac{200N}{9.8m/s^2} = 20.4kg\)