Problem
Part 3 of 6 Points: 2 of 6 A certain drug is used to treat asthma. In a clinical trial of the drug, 22 of 260 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than $8 \%$ of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts (a) through (e) below. \[ \begin{array}{l} \hline \text {-PropzTost } \\ \text { prop<0.08 } \\ z=0.274318898 \\ p=0.6080802032 \\ \hat{p}=0.0846153846 \\ n=260 \end{array} \] b. What is the test statistic? \[ z=0.27 \] (Round to two decimal places as needed.) c. What is the P-value? \[ \text { P-value }=\square \] (Round to four decimal places as needed.)
Solution
Step 1 ：The test statistic is given in the question as \(z=0.274318898\). We need to find the P-value.
Step 2 ：The P-value is also given in the question as \(p=0.6080802032\). We just need to round it to four decimal places.
Step 3 ：\(p_{value} = 0.6081\)
Step 4 ：Final Answer: The P-value is \(\boxed{0.6081}\).
