For each ordered pair, determine whether it is a solution to the system of equations. \[ \left\{\begin{array}{c} 3 x-2 y=7 \\ y=2 x-8 \end{array}\right. \] \begin{tabular}{|c|c|c|} \hline \multirow{2}{*}{$(x, y)$} & \multicolumn{2}{|c|}{ Is it a solution? } \\ \cline { 2 - 3 } & Yes & No \\ \hline$(-1,-5)$ & & $\bigcirc$ \\ \hline$(2,-4)$ & & $\bigcirc$ \\ \hline$(-6,0)$ & $\bigcirc$ & $\bigcirc$ \\ \hline$(9,10)$ & & \\ \hline \end{tabular}

Step 1 ：Given the system of equations: \[\left\{\begin{array}{c} 3 x-2 y=7 \\ y=2 x-8 \end{array}\right.\]

Step 2 ：We need to check if each pair of (x, y) satisfies both equations. We can do this by substituting the x and y values from each pair into the equations and checking if both equations hold true.

Step 3 ：Let's check the first pair (-1, -5). Substituting these values into the equations, we find that they do not satisfy both equations.

Step 4 ：Next, we check the pair (2, -4). Again, substituting these values into the equations, we find that they do not satisfy both equations.

Step 5 ：Checking the pair (-6, 0), we find that it does not satisfy both equations.

Step 6 ：Finally, we check the pair (9, 10). Substituting these values into the equations, we find that they satisfy both equations.

Step 7 ：Therefore, the ordered pair that is a solution to the system of equations is \(\boxed{(9, 10)}\).