on 11.7 Homework Question 7, 11.7.41 HW Score: $33.33 \%, 5$ of 15 points Points: 0 of 1 If a club consists of 9 members, how many different arrangements of president, vice-president, and secretary are possible? The number of possible arrangements is $\square$.

Step 1 ：We are given a club with 9 members and we are asked to find the number of different arrangements of president, vice-president, and secretary.

Step 2 ：This is a permutation problem, where order matters. We are choosing 3 people (president, vice-president, and secretary) from a group of 9.

Step 3 ：The formula for permutations is \( P(n, r) = \frac{n!}{(n-r)!} \), where n is the total number of items, r is the number of items to choose, and '!' denotes factorial.

Step 4 ：Substituting the given values into the formula, we get \( P(9, 3) = \frac{9!}{(9-3)!} \).

Step 5 ：Calculating the factorials and simplifying, we find that the number of different arrangements is 504.

Step 6 ：Final Answer: The number of possible arrangements is \( \boxed{504} \).