Problem

The length of the vector $\left[\begin{array}{c}3 \\ 2 \\ -2 \\ -3\end{array}\right]$ is $\square$.

Solution

Step 1 :Define the vector as \(\left[\begin{array}{c}3 \ 2 \ -2 \ -3\end{array}\right]\).

Step 2 :Calculate the length of the vector using the formula \(\sqrt{\sum_{i=1}^{n} a_i^2}\), where \(a_i\) are the components of the vector.

Step 3 :Substitute the values into the formula to get \(\sqrt{3^2 + 2^2 + (-2)^2 + (-3)^2}\).

Step 4 :Simplify the expression to get \(\sqrt{9 + 4 + 4 + 9}\).

Step 5 :Further simplify the expression to get \(\sqrt{26}\).

Step 6 :Calculate the square root of 26 to get approximately 5.099.

Step 7 :Final Answer: The length of the vector is \(\boxed{5.099}\).

From Solvely APP
Source: https://solvelyapp.com/problems/5cpkSTFPWu/

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