Find the equation of a line that passes through the point \((2,3)\) and has a slope of \(4\).

Step 1 ：Step 1: Recall the slope-intercept form of a linear equation: \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.

Step 2 ：Step 2: Substitute the slope \(m = 4\) into the equation to get: \(y = 4x + b\).

Step 3 ：Step 3: Substitute the point \((2,3)\) into the equation to solve for \(b\): \(3 = 4*2 + b\).

Step 4 ：Step 4: Simplify the equation to solve for \(b\): \(3 = 8 + b\), \(b = -5\).

Step 5 ：Step 5: Substitute \(b = -5\) back into the equation to get the final equation of the line: \(y = 4x - 5\).