Problem

Use the long division method to find the result when $9 x^{3}+6 x^{2}+28 x+9$ is divided by $3 x+1$. Answer Atempt iout of:

Solution

Step 1 :\(\frac{9x^3}{3x} = 3x^2\)

Step 2 :\((9x^3 + 6x^2) - (3x^2(3x+1)) = 3x^2 + 28x + 9\)

Step 3 :\(\frac{3x^2}{3x} = x\)

Step 4 :\((3x^2 + 28x + 9) - (x(3x+1)) = 27x + 9\)

Step 5 :\(\frac{27x}{3x} = 9\)

Step 6 :\((27x + 9) - (9(3x+1)) = 0\)

Step 7 :\(\boxed{3x^2 + x + 9}\)

From Solvely APP
Source: https://solvelyapp.com/problems/5CPgJ27llZ/

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