эpplicable, give the solution. \begin{tabular}{|c|c|} \hline \begin{tabular}{c} System A \\ $-x-5 y=5$ \\ $x+5 y-5=0$ \end{tabular} & \begin{tabular}{l} The system has no solution. \\ The system has a unique solution: \\ $(x, y)=$ \\ The system has infinitely many solutions. \\ They must satisfy the following equation: \\ $y=\square$ \end{tabular} \\ \hline \begin{tabular}{r} System B \\ $-x+2 y=6$ \\ $x+2 y=6$ \end{tabular} & \begin{tabular}{l} The system has no solution. \\ The system has a unique solution: \\ $(x, y)=$ \\ The system has infinitely many solutions. \\ They must satisfy the following equation: \\ $y=\square$ \end{tabular} \\ \hline \end{tabular} Explanation Check

Step 1 ：We are given two systems of linear equations. System A consists of the equations -x - 5y = 5 and x + 5y - 5 = 0. System B consists of the equations -x + 2y = 6 and x + 2y = 6.

Step 2 ：We start by solving System A. After simplifying the equations, we find that they are contradictory, meaning that System A has no solution.

Step 3 ：Next, we solve System B. After simplifying the equations, we find that they are identical, meaning that System B has a unique solution.

Step 4 ：By substituting the value of x from the second equation of System B into the first equation, we find that y = 3.

Step 5 ：Substituting y = 3 back into the second equation of System B, we find that x = 0.

Step 6 ：Therefore, the solution to System B is \((x, y) = \boxed{(0, 3)}\).

Step 7 ：In conclusion, System A has no solution and System B has a unique solution \((x, y) = \boxed{(0, 3)}\).