Step 1 :Given the exam scores for a traditional and a flipped classroom, we are asked to determine which course has more dispersion in exam scores using the range as the measure of dispersion.
Step 2 :The range is calculated as the difference between the maximum and minimum values.
Step 3 :For the traditional course, the scores are: 70.1, 68.4, 80.2, 67.3, 85.0, 77.9, 56.9, 81.2, 80.7, 70.5, 64.3, 70.7, 60.7. The range of these scores is \(85.0 - 56.9 = 28.1\).
Step 4 :For the flipped course, the scores are: 76.5, 72.3, 62.9, 73.4, 77.5, 90.7, 79.2, 77.2, 82.2, 70.4, 91.2, 77.4, 77.5. The range of these scores is \(91.2 - 62.9 = 28.3\).
Step 5 :Comparing the ranges, we find that the flipped course has a larger range than the traditional course.
Step 6 :\(\boxed{\text{Therefore, the flipped course has more dispersion in exam scores.}}\)