Geaphs and Rumetions twpressing a function as a composition of two functions Suppose $H(x)=6 \sqrt[3]{x}+5$ Find two functions $f$ and $g$ such that $(f \circ g)(x)=\|(x)$, Neither function can be the identity function. (There may be more than one correct answer.)

Step 1 ：The function H(x) can be expressed as a composition of two functions f and g. We can break down H(x) into two parts: the cube root part and the linear part.

Step 2 ：We can let f(x) be the linear function and g(x) be the cube root function.

Step 3 ：Let's define the functions as follows: \(f(x) = 6x + 5\) and \(g(x) = \sqrt[3]{x}\).

Step 4 ：Substituting g(x) into f(x), we get \(f(g(x)) = 6g(x) + 5 = 6\sqrt[3]{x} + 5\), which is equal to H(x).

Step 5 ：\(\boxed{\text{Final Answer: The functions f and g that satisfy the condition }(f \circ g)(x)=H(x)\text{ are }f(x)=6x+5\text{ and }g(x)=\sqrt[3]{x}.}\)