Problem

A rose garden is formed by joining a rectangle and a semicircle, as shown below. The rectangle is $28 \mathrm{ft}$ long and $21 \mathrm{ft}$ wide. If the gardener wants to build a fence around the garden, how many feet of fence are required? (Use the value 3.14 for $\pi$, and do not round your answer. Be sure to include the correct unit in your answêr.) $\square$ ft $\mathrm{ft}^{2}$ $\mathrm{ft}^{3}$ $x$ 5

Solution

Step 1 :Given that the rose garden is formed by joining a rectangle and a semicircle, with the rectangle being $28 \mathrm{ft}$ long and $21 \mathrm{ft}$ wide.

Step 2 :The fence will be along the perimeter of the rectangle and the circumference of the semicircle.

Step 3 :The perimeter of a rectangle is given by the formula \(2 \times (\text{length} + \text{width})\). Substituting the given values, we get \(2 \times (28 + 21) = 98 \mathrm{ft}\).

Step 4 :The circumference of a circle is given by the formula \(2 \times \pi \times \text{radius}\). Since we only have a semicircle, we will take half of the circumference. The radius of the semicircle is equal to the width of the rectangle, which is $21 \mathrm{ft}$. So, the circumference of the semicircle is \(\pi \times 21 = 65.97 \mathrm{ft}\).

Step 5 :Adding these two values together, we get the total length of the fence required: \(98 + 65.97 = 163.97 \mathrm{ft}\).

Step 6 :Final Answer: The gardener requires \(\boxed{163.97}\) feet of fence to build around the garden.

From Solvely APP
Source: https://solvelyapp.com/problems/4DvVbJ96gP/

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