2 3 4 5 Suppose that the functions $h$ and $g$ are defined as follows. \[ \begin{array}{l} h(x)=x+6 \\ g(x)=(x-4)(x-2) \end{array} \] (a) Find $\left(\frac{h}{g}\right)(5)$. (b) Find all values that are NOT in the domain of $\frac{h}{g}$ If there is more than one value, separate them with commas. (a) $\left(\frac{6}{3}\right)(5)=0$

Step 1 ：For part (a), we need to find the value of \(\left(\frac{h}{g}\right)(5)\). This means we need to substitute \(x=5\) into the function \(\frac{h(x)}{g(x)}\).

Step 2 ：For part (b), the values that are not in the domain of \(\frac{h}{g}\) are the values of \(x\) for which \(g(x) = 0\), because division by zero is undefined in mathematics. So we need to solve the equation \(g(x) = 0\) to find these values.

Step 3 ：Final Answer: (a) \(\left(\frac{h}{g}\right)(5) = \boxed{0.5}\)

Step 4 ：Final Answer: (b) Value(s) that are NOT in the domain of \(\frac{h}{g}\) : \(\boxed{2,4}\)