Find an equation of the line having a slope of -1 and point $(6,-2)$. Write the answer in slope-intercept form $y=m x+b$. \[ y= \]

Step 1 ：The equation of a line in slope-intercept form is given by \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.

Step 2 ：We are given that the slope \(m\) is -1 and the line passes through the point \((6, -2)\). We can substitute these values into the equation to find the y-intercept \(b\).

Step 3 ：Substituting the given values, we get \(b = 4\).

Step 4 ：Now that we have the slope and the y-intercept, we can substitute these values into the slope-intercept form to get the equation of the line.

Step 5 ：Substituting \(m = -1\) and \(b = 4\) into the equation, we get \(y = -1x + 4\).

Step 6 ：Final Answer: The equation of the line is \(\boxed{y = -x + 4}\).