Solve the quadratic equation by completing the square. \[ x^{2}-6 x-2=0 \] First, choose the appropriate form and fill in the blanks with the correct numbers. Then, solve the equation. If there is more than one solution, separate them with commas. Form: $(x+\square)^{2}=$ $(x-\square)^{2}=$ Solution: \[ x= \]

Step 1 ：The given quadratic equation is in the form of \(ax^2 + bx + c = 0\). To solve this equation by completing the square, we need to rewrite the equation in the form of \((x + d)^2 = e\) or \((x - d)^2 = e\), where \(d\) and \(e\) are constants.

Step 2 ：The first step is to rewrite the equation as \(x^2 - 6x = 2\).

Step 3 ：Then, we need to add \((b/2a)^2\) to both sides of the equation to complete the square on the left side. In this case, \(b = -6\) and \(a = 1\), so \((b/2a)^2 = (-6/2*1)^2 = 9\).

Step 4 ：After adding 9 to both sides, the equation becomes \((x - 3)^2 = 11\).

Step 5 ：Finally, we can solve for \(x\) by taking the square root of both sides. This will give us two solutions, \(x = 3 + \sqrt{11}\) and \(x = 3 - \sqrt{11}\).

Step 6 ：The solutions to the equation \(x^{2}-6 x-2=0\) are \(x = -0.3542486889354093\) and \(x = -5.645751311064591\). In LaTeX format, the solutions are \(x = \boxed{-0.3542486889354093}\) and \(x = \boxed{-5.645751311064591}\).