Problem
Let \[ f(x)=(x-6)^{2} \] Find a domain on which $f$ is one-to-one and non-decreasing. Find the inverse of $f$ restricted to this domain \[ f^{-1}(x)= \] Question Help: $\square$ Video $\square$ Message instructor Submit Question Jump to Answer
Solution
Step 1 ：\(y = (x-6)^2\)
Step 2 ：\(x = (y-6)^2\)
Step 3 ：\(\sqrt{x} = y - 6\)
Step 4 ：\(\boxed{y = \sqrt{x} + 6}\)
