— Save \& Exit Practice Lesson: 3.4 Slope and Forms of Linear Equ... Question 8 of 11 , Step 2 of 3 $9 / 15$ Correct Consider the following equation. \[ -3 x+y-12=0 \] Step 2 of 3: Plot the point on the line with the $x$-coordinate $\mathrm{x}=-3$. Answer Points can be moved by dragging or using the arrow keys.

Step 1 ：Consider the following equation: \(-3x + y - 12 = 0\).

Step 2 ：We are asked to plot the point on the line with the x-coordinate \(x = -3\).

Step 3 ：To find the y-coordinate of this point, we substitute \(x = -3\) into the equation and solve for y.

Step 4 ：This gives us the equation \(y - 3 = 0\).

Step 5 ：Solving for y, we find that \(y = 3\).

Step 6 ：Final Answer: The point on the line with the x-coordinate \(x = -3\) is \((-3, 3)\). So, the y-coordinate is \(\boxed{3}\).