4. Has slope of 5 and passes through $(6,1)$

Step 1 ：The question is asking for the equation of a line that has a slope of 5 and passes through the point (6,1). The general form of a linear equation is \(y = mx + b\), where m is the slope and b is the y-intercept.

Step 2 ：We know the slope (m) is 5, and we can find b by substituting the given point into the equation and solving for b.

Step 3 ：Substituting the given point (6,1) into the equation \(y = mx + b\), we get \(1 = 5*6 + b\). Solving for b, we find that b = -29.

Step 4 ：Now that we have the slope (m) and the y-intercept (b), we can write the equation of the line.

Step 5 ：The equation of the line is \(\boxed{y = 5x - 29}\).