Solving a percent mixture problem using a linear equation $3 / 5$ Two factory plants are making TV panels. Yesterday, Plant A produced 8000 panels. Four percent of the panels from Plant A and $1 \%$ of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was $2 \%$ ? Number of panels produced by Plant B: \] Explanation Check

Step 1 ：Let's denote the number of panels produced by Plant B as x. The total number of defective panels is the sum of the defective panels from Plant A and Plant B, which is \(0.04*8000 + 0.01*x\). The total number of panels is \(8000 + x\).

Step 2 ：The overall percentage of defective panels is the total number of defective panels divided by the total number of panels, which is \((0.04*8000 + 0.01*x) / (8000 + x) = 0.02\).

Step 3 ：We can solve this equation for x.

Step 4 ：The solution to the equation is 16000. This means that Plant B produced 16000 panels.

Step 5 ：Final Answer: \(\boxed{16000}\)