2 1 point What is the density in $\mathrm{g} / \mathrm{cm}^{3}$ of an unknown material if a cube of the material measures $3.60 \mathrm{~cm}$ on a side and has a mass of $3.19 \mathrm{~g}$ ? (you do not need to put in the units with your answer) Make sure vour answer is written to the correct number of significant figures to receive full credit. Type your answer- Previous

Step 1 ：The density of a material is calculated by the formula: Density = Mass / Volume.

Step 2 ：Given that the cube measures 3.60 cm on a side, the volume of the cube can be calculated using the formula for the volume of a cube: Volume = side^3.

Step 3 ：First, calculate the volume of the cube: \(3.60^3 = 46.656 \, \mathrm{cm^3}\).

Step 4 ：Then, use the calculated volume to find the density: \(\frac{3.19 \, \mathrm{g}}{46.656 \, \mathrm{cm^3}} = 0.06837277091906721 \, \mathrm{g/cm^3}\).

Step 5 ：However, the question asks for the answer to be written to the correct number of significant figures. The given values, 3.19 g and 3.60 cm, both have three significant figures. Therefore, the density should also be reported with three significant figures.

Step 6 ：Final Answer: The density of the unknown material is \(\boxed{0.068 \, \mathrm{g/cm^3}}\).