\[ \begin{array}{l} s(x)=2 x+1 \\ t(x)=-2 x^{2}+1 \end{array} \] Find the value of $t(s(4))$

Step 1 ：First, we need to find the value of \(s(4)\) by substituting \(x = 4\) into the function \(s(x) = 2x + 1\).

Step 2 ：So, \(s(4) = 2*4 + 1 = 9\).

Step 3 ：Then, we substitute the result into the function \(t(x) = -2x^2 + 1\) to find the value of \(t(s(4))\).

Step 4 ：Substituting \(s(4) = 9\) into \(t(x)\), we get \(t(9) = -2*9^2 + 1 = -161\).

Step 5 ：So, the final answer is \(\boxed{-161}\).