Score: $1 / 3$ Penalty: none Question Watch Video Find all angles, $0^{\circ} \leq \theta<360^{\circ}$, that solve the following equation. \[ \sin \theta=-\frac{\sqrt{2}}{2} \] Answer Attempt 1 out of 2 Additional Solution No Solution \[ \theta= \] Submit Answer

Step 1 ：The given equation is \(\sin \theta=-\frac{\sqrt{2}}{2}\).

Step 2 ：We know that sine is negative in the third and fourth quadrants.

Step 3 ：The reference angle for \(\frac{\sqrt{2}}{2}\) is \(45^\circ\).

Step 4 ：So the solutions to the equation are \(180^\circ + 45^\circ\) and \(360^\circ - 45^\circ\).

Step 5 ：angle1 = 225

Step 6 ：angle2 = 315

Step 7 ：Final Answer: The solutions to the equation are \(\boxed{225^\circ}\) and \(\boxed{315^\circ}\).