Find the equation of the line using the point-slope formula. Write the final equation using the slope-intercept form. the $x$-intercept is 1 , and $(x, y)=(-2,3)$ is a point on the line

Step 1 ：We are given that the line passes through the point (-2,3) and has an x-intercept of 1. This means the line also passes through the point (1,0).

Step 2 ：We can find the slope of the line using the formula \(m = \frac{y_2 - y_1}{x_2 - x_1}\). Substituting the given points into this formula, we get \(m = \frac{0 - 3}{1 - (-2)} = -1.0\).

Step 3 ：Next, we use the point-slope form of the line equation, which is \(y - y_1 = m(x - x_1)\). Substituting the point (-2,3) and the slope -1.0 into this formula, we get \(y - 3 = -1.0(x - (-2))\).

Step 4 ：Solving this equation for y, we get \(y = -1.0x + 1.0\).

Step 5 ：Finally, we can write the equation of the line in slope-intercept form, which is \(y = mx + b\). Substituting the slope -1.0 and the y-intercept 1.0 into this formula, we get \(y = -1.0x + 1.0\).

Step 6 ：\(\boxed{y = -x + 1}\) is the equation of the line.