Step 1 :Find the derivative of the function \(h(x)=3x^3-9x\).
Step 2 :The derivative of the function is \(h'(x)=9x^2-9\).
Step 3 :Set the derivative equal to zero and solve for x to find the critical points: \(9x^2-9=0\).
Step 4 :The critical points are -1 and 1.
Step 5 :Test the intervals around the critical points by plugging in values into the derivative. We will test the intervals \((-\infty, -1)\), \((-1, 1)\), and \((1, \infty)\).
Step 6 :The function is increasing on the intervals \((-\infty, -1)\) and \((1, \infty)\), and decreasing on the interval \((-1, 1)\).
Step 7 :\(\boxed{\text{The function is increasing on } (-\infty, -1) \text{ and } (1, \infty). \text{ The function is decreasing on } (-1, 1).}\)