Step 1 :The slope of line $d$ is the same as the slope of line $c$ because they are parallel. The slope of line $c$ is $5$. So, the slope of line $d$ is also $5$.
Step 2 :We can use the point-slope form of a line to find the equation of line $d$. The point-slope form of a line is $y - y_1 = m(x - x_1)$, where $(x_1, y_1)$ is a point on the line and $m$ is the slope of the line.
Step 3 :We can substitute $(2,6)$ for $(x_1, y_1)$ and $5$ for $m$ to find the equation of line $d$.
Step 4 :The equation of line $d$ is $5x - y = 4$. However, we need to write the equation in slope-intercept form, which is $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept. We can rearrange the equation to this form.
Step 5 :The equation of line $d$ in slope-intercept form is $y = 5x - 4$.
Step 6 :\(\boxed{y = 5x - 4}\)